Question

Integrate the following w.r.t:cos (4x+3)

• A.
• B.
• C. sin(4x+3)+c
• D. -sin(4x+3)+c

Answer 1

The correct option is A

Let $u$ =4x+3
$\Rightarrow \frac{du}{dx}=4$

$\Rightarrow dx=\frac{du}{4}$

$I=\int cos(4x+3)dx=\int \frac{cosu}{4}du$

= $\frac{1}{4}sinu+c$

= $\frac{1}{4}sin(4x+3)+c$