Integrate the following w.r.t. $x$
$cos (4 x + 3)$ .

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Solution

$y = cos (4 x + 3)$
Integrating both sides w.r.t. $x$ , we get
$I = \int y d x = \int cos (4 x + 3) d x = \frac{sin (4 x + 3)}{4} + c$ .

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