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Question

Integrate the following w.r.t. x
e2x+1x2.

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Solution

y=e2x+1x2
Integrating both sides w.r.t. x, we get
I=y dx=(e2x+1x2)dx
=e2x2+x2+12+1+c[eax=eaxa+c]
=e2x21x+c.

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