Question

Integrate the following w.r.t. $x$.
$y=x-\frac{1}{x}$.

Answer 1

$y=x-\frac{1}{x}$
Integrating both sides w.r.t. $x$, we get
$I=\int ydx=\int (x-\frac{1}{x})dx[\because \int \frac{1}{x}dx=lnx+c]$
$=\frac{x^2}{2}-lnx+c$.