wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Integrate the function 1x12+x13

Open in App
Solution

1x12+x13=1x13(1+x16)
Let x=t6dx=6t5dt
1x12+x13dx=1x13(1+x16)dx
=6t5t2(1+t)dt
=6t3(1+t)dt
On dividing, we obtain
1x12+x13dx=6{(t2t+1)11+t}dt
=6[(t33)(t22)+tlog|1+t|]
=2x123x13+6x166log(1+x16)+C
=2x3x13+6x166log(1+x16)+C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Partial Fractions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon