Integrate the function $e^{2 x + 3}$

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Solution

Put $2 x + 3 = t$
$∴ 2 d x = d t$
$\Rightarrow e^{2 x + 3} d x = \frac{1}{2} \int e^{t} d t$
$= \frac{1}{2} (e^{t}) + C$
$= \frac{1}{2} e^{(2 x + 3)} + C$

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