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Question

Integrate the function.
xsec2xdx.

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Solution

Let I=xsec2xdx.
On taking x as first function and sec2 x as second function and integrating by parts, we get
I=xsec2xdx[ddx(x)sec2xdx]dx
=xtanxtanxdx=xtanxlog|secx|+CI=xtanx+log|cosx|+C[log|secx|=log1cosx=log1log|cosx|=log|cosx|(log=0)]


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