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Question

Integrate the given function defined over a proper domain w.r.t. x : x36x2+10x2x25x+6

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Solution

x36x2+10x2x25x+6dx
=(x1)dx+x+4x25x+6dx
=x22xx4x25x+6dx
=x22xx31x25x+6dx
=x22xx3x25x+6dx+dxx25x+6
=x22xx3(x3)(x2)dx+[(x3)(x2)]dx(x3)(x2)
=x22xdx(x2)+[(x3)(x2)]dx(x3)(x2)
=x22xlog|x2|+(x3)dx(x3)(x2)(x2)dx(x3)(x2)
=x22xlog|x2|+dx(x2)dx(x3)
=x22xlog|x2|+log|x2|log|x3|+c
=x22xlog|x3|+c

1512098_1180601_ans_608dc034840e4b53a7e9e4511510948f.PNG

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