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Question

Integrate the rational function 2(1x)(1+x2)

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Solution

Let 2(1x)(1+x2)=A(1x)+Bx+C(1+x2)
2=A(1+x2)+(Bx+C)(1x)
2=A+Ax2+BxBx2+C+Cx
Equating the coefficient of x2,x, and constant term, we obtain
AB=0
BC=0
A+C=2
On solving these questions, we obtain
A=1,B=1, and C=1
2(1x)(1+x2)=11x+x+11+x2
2(1x)(1+x2)dx=11xdx+x1+x2dx+11+x2dx
=1x1dx+122x1+x2dx+11+x2dx
=log|x1|+12log|1+x2|+tan1x+C

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