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Question

Integrate the rational functions.
1ex1dx

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Solution

Let I=1ex1dx
On multiplying numerator and denominator by ex, we get
I=ex1exdx
Put 1ex=tex(1)=dtdxdx=dtexexdx=dt
I=dtt=log|t|+C=log|1ex|+C=logex1ex+C


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