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Question

Integrate the rational functions.
2xx2+3x+2dx.

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Solution

Let 2xx2+3x+2=2xx2+2x+x+2
=2xx(x+2)+1(x+2)=2x(x+2)(x+1)
Let 2x(x+2)(x+1)=A(x+2)+B(x+1)
2x(x+2)(x+1)=A(x+1)+B(x+2)(x+2)(x+1)2x=Ax+A+Bx+2B2x=x(A+B)+(A+2B).
On comparing the coefficients of x and constant term on both sides, we get
A+B=2 .....(i)
and A+2B=0 .....(ii)
On subtracting Eq. (ii)form Eq. (i), we get -B =2 B =-2
On putting the value of B in Eq. (i),we get A-2=2 A =4
2x(x+2)(x+1)dx=A(x+2)dx+B(x+1)dx=4(x+2)dx+(2)(x+1)dx=4log|x+2|2log|x+1|+C


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