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Question

Integrate wrt x 1(3x+4)(3x+1)+8x+13(4x+7)+(7x2)3x+2.

A
13[13.23(3x+4)3/2+13.23(3x+1)3/2+2.14.23(4x+7)3/214.24x+7]
+73[13.25(3x+2)5/2207.13.23(3x+2)3/2]
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B
13[13.23(3x+4)3/2+13.23(3x+1)3/2+2.14.23(4x+7)3/214.24x+7]
79[13.25(3x+2)5/2207.13.23(3x+2)3/2]
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C
13[13.23(3x+4)3/213.25(3x+1)3/2+2.14.23(4x+7)3/214.24x+7]
53[13.25(3x+2)5/2207.13.23(3x+2)3/2]
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D
None
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Solution

The correct option is A 13[13.23(3x+4)3/2+13.23(3x+1)3/2+2.14.23(4x+7)3/214.24x+7]
+73[13.25(3x+2)5/2207.13.23(3x+2)3/2]
(i)1(3x+4)(3x+1)=3x+4+3x+1(3x+4)(3x+1).
=13[3x+4+3x+1].
(ii)8x+13(4x+7)=2(4x+7)1(4x+7)=24x+714x+7
(iii)(7x2)(3x+2)=73(3x67)3x+2
Hence I=73(3x+2672)3x+2.
=73[(3x+2)3/22073x+2].
13[13.23(3x+4)3/2+13.23(3x+1)3/2+2.14.23(4x+7)3/214.24x+7]
+73[13.25(3x+2)5/2207.13.23(3x+2)3/2].

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