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Question

Integrate x tanx.

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Solution

Given xtanxdx
Using the rule of uvdx=uvdx[uvdx]dx
Now, replace u=x and v=tanx, we get
xtanxdx=xtanxdx[(x)tanxdx]dx
=xlncosx+lncosxdx [Since, tanx=lncosx+c]
xtanxdx=xln|cosx|+cosxln|cosx|cosx+c [Since ln|x|=xlnxx+c]


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