Intensity of electric field obtained at receiver antenna for a space wave propagation is

directly proportional to the perpendicular-distance from transmitter to antenna

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inversely proportional to the perpendicular-distance from transmitter to antenna

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directly proportional to the square perpendicular distance from transmitter to antenna

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inversely proportional to the square perpendicular distance from transmitter to antenna

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Solution

The correct option is D inversely proportional to the square perpendicular distance from transmitter to antenna
The field strength due to space wave propagation is given by: $| E | = (\frac{4 π H h}{λ d^{2}}) E_{0}$
where $H, h$ are heights of transmitter and receiver respectively.
$d$ is the perpendicular distance between transmitter and receiver
$E_{0}$ is electric field emitted from transmitting antenna

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