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Question

Intensity of light beam is doubled by doubling the frequency then saturation photocurrent will be

A
Doubled
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B
Halved
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C
Remain same
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D
None of these
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Solution

The correct option is A Doubled

For photoemission the frequency of the incident light must be greater than a specific frequency called cut-off frequency. If the frequency is less than that photoemission would not happen irrespective of the light intensity. If we assume that the initial frequency was greater then the cut-off frequency then doubling the frequency will also cause photoemission and we will get some non-zero photocurrent.

However the intensity is the measure of number of incident photons per second per unit area. So, doubling its value will double the probability of collision with atoms, hence, doubling the value of photocurrent.

Note; Here we have considered that the photocurrent is below the saturation limits. In real case, the current does not increase indefinitely with increase in intensity. As the number available atoms for photoelectric effect is finite, the maximum value of current is also finite and it gets saturated after certain intensity.


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