Interference fringes are obtained using 2 coherent sources whose intensities are in the ratio 9:4. Then ratio of the intensities of the bright and dark bands is

5:1

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9:4

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25:1

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4:1

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Solution

The correct option is C
25:1

$\frac{I_{1}}{I_{2}} = \frac{9}{4} \frac{I_{m a x}}{I_{m i n}} = \frac{(\sqrt{I_{1}} + \sqrt{I_{2}})^{2}}{(\sqrt{I_{1}} - \sqrt{I_{2}})^{2}} \frac{(3 + 2)^{2}}{(3 - 2)^{2}} = \frac{25}{1}$

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Interference fringes are obtained using 2 coherent sources whose intensities are in the ratio 9:4. Then ratio of the intensities of the bright and dark bands is

The correct option is C 25:1 I1I2=94ImaxImin=(√I1+√I2)2(√I1−√I2)2(3+2)2(3−2)2=251

The correct option is C
25:1

$\frac{I_{1}}{I_{2}} = \frac{9}{4} \frac{I_{m a x}}{I_{m i n}} = \frac{(\sqrt{I_{1}} + \sqrt{I_{2}})^{2}}{(\sqrt{I_{1}} - \sqrt{I_{2}})^{2}} \frac{(3 + 2)^{2}}{(3 - 2)^{2}} = \frac{25}{1}$