Interference fringes in Young’s double slit experiment with monochromatic light are:
A
always equispaced
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B
always unequally spaced
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C
both equally and unequally spaced
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D
formed by a portion of the wave front
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Solution
The correct option is A always equispaced Fringe width =λDd As the λ (wavelength), D (distance of screen from the slits) and, d (distance between the slits) remain the same, fringe width remains the same. Hence all fringes are always equispaced.