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Standard XII

Chemistry

Difference between Internal Energy and Enthalpy

Internal ener...

Question

Internal energy change for combustion of oxalic acid ( $H_{2} C_{2} O_{4}$ ) is $- 245.7 k J / m o l$ . The enthalpy of the combustion of oxalic acid at $27^{o}$ C is:

- 341.95

kJ/mol

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- 241.95

kJ/mol

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- 182.86 k J / m o l

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- 210.68 k J / m o l

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Solution

The correct option is B $- 241.95$ kJ/mol
$H_{2} C_{2} O_{4} (l) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) + 2 C O_{2} (g)$
$Δ n_{g}$ = difference in moles of gaseous products and reactants = $2 - \frac{1}{2}$ = $\frac{3}{2}$
$Δ H = Δ U + n_{g} R T$ = $- 245.7 + \frac{\frac{3}{2} \times 8.314 \times 300}{1000}$ = $- 241.95$ kJ/mol

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Similar questions

Q. Internal energy change for combustion of oxalic acid (

H_{2} C_{2} O_{4}

) is

- 245.7 k J / m o l

. The enthalpy of the combustion of oxalic acid at

27^{o}

C is:

When $1.0 g$ of oxalic acid ( $H_{2} C_{2} O_{4})$ is burned in a bomb calorimeter whose heat capacity is $8.75 k J / K$ , the temperature increased by $0.312 K$ . The enthalpy of combustion of oxalic acid at $27^{\circ} C$ .

Q. When

1.0 g

of oxalic acid

(H_{2} C_{2} O_{4})

is burned in a bomb calorimeter whose heat capacity is

8.75 k J / K

, the temperature increases by

0.312 K

. The enthalpy of combustion of oxalic acid at

27^{o} C

is:

Q. When 1 g of anhydrous oxalic acid is burnt at

25^{0} C

, the amount of heat liberated is

2.835 k J

△ H

combustion is: (oxalic acid:

C_{2} H_{2} O_{4}

Q. Assertion :Statement-1 : The enthalpy of neutralization of the reaction between HCl and NaOH is -13.7 kCal/mol. If the enthalpy of neutralization of oxalic acid

(H_{2} C_{2} O_{4})

by a strong base is -25.4 kCal/mol, then the enthalpy change

(Δ H)

of the process

H_{2} C_{2} O_{4} \to 2 H^{+} + C_{2} O_{4}^{2 -}

is 11.7 kCal/mol. Reason: Statement -2 :

H_{2} C_{2} O_{4}

is a weak acid.

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Difference between Internal Energy and Enthalpy

Standard XII Chemistry

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Internal energy change for combustion of oxalic acid (H2C2O4) is −245.7 kJ/mol. The enthalpy of the combustion of oxalic acid at 27o C is:

The correct option is B −241.95 kJ/molH2C2O4(l)+12O2(g)→H2O(l)+2CO2(g) Δng = difference in moles of gaseous products and reactants = 2−12 = 32 ΔH=ΔU+ngRT = −245.7+32×8.314×3001000 = −241.95 kJ/mol

Internal energy change for combustion of oxalic acid ( $H_{2} C_{2} O_{4}$ ) is $- 245.7 k J / m o l$ . The enthalpy of the combustion of oxalic acid at $27^{o}$ C is: