Internal energy of a system increases by 60 J when 140 J of heat is added to the gaseous system. The amount of work done would be:

200 J

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80 J

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100 J

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140 J

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Solution

The correct option is B
80 J

dW = dQ - dU = 140 - 60 = 80 J

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If the heat 110 J is added to a gaseous system and it acquires internal energy of 40 J, then the amount of internal work done is

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