Question

Into a circular drum of radius$\mathbf{}\mathbf{4}\mathbf{.}\mathbf{8}\mathbf{}\mathbf{m}$ and height $\mathbf{3}\mathbf{.}\mathbf{5}\mathbf{}\mathbf{m}$, how many full bags of wheat can be emptied if the space required for wheat in each bag is $\mathbf{2}\mathbf{.}\mathbf{1}\mathbf{}{\mathbf{m}}^{\mathbf{3}}$.

Answer 1

Step 1: Given information.

The radius, $r=4.8\mathrm{m}$

The height, $h=3.5\mathrm{m}$

Step 2: Find the number of required wheat bags.

The volume of the drum,

$$\begin{gathered} V=\mathrm{\pi }{r}^{2}h \\ =3.14\times {\left(4.8\right)}^2\times 3.5 \\ =3.14\times 4.8\times 4.8\times 3.5 \\ =253.2096{\mathrm{m}}^3 \end{gathered}$$

And the volume of each bag of wheat$=2.1{\mathrm{m}}^3$

Therefore, the required number of bags:

$$\begin{gathered} =\frac{253.2096}{2.1} \\ =120.576 \\ =120\mathrm{bags} \end{gathered}$$

Hence,$120$ full bags of wheat can be emptied.