Iodine is liberated in the reaction between KI and Cu2+ but chlorine is not liberated when KCl is added to Cu+. If true enter 1, else enter 0.
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Solution
The correct option is A 1 The I− ion acts as strong reducing agent where as Cl− acts as reductant only in presence of strong oxidant and therefore KI reduces Cu2+ to Cu+ Cu2++4KI⟶Cu2I2+I2+4K+