Iodine is released when potassium iodide reacts with

Z n S O_{4}

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C u S O_{4}

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F e S O_{4}

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(N H_{4})_{2} S O_{4}

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Solution

The correct options are
B $C u S O_{4}$
C $F e S O_{4}$
D $(N H_{4})_{2} S O_{4}$
B] $C u S O_{4} + 4 K I \to 2 C u I + 2 K_{2} S O_{4} + I_{2}$

C] $2 K I + C l_{2} \to 2 K C l + I_{2}$

D] $2 K I + B r_{2} \to 2 K B r + I_{2}$

Hence, Options "B", "C" & "D" are correct answers.

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Iodine is formed when potassium iodide reacts with:

1

H_{2} S O_{4}

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