Iodine oxidises sodium borohydride to give

B_{2} H_{6}

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sodium hydride

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H I

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I_{3}^{-}

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Solution

The correct option is A $B_{2} H_{6}$
The oxidation of sodium borohydride with iodine in diglyme gives diborane.

$2 N a B H_{4} + I_{2} Diglyme - ---- \to B_{2} H_{6} + 2 N a I + H_{2}$

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Similar questions

The product obtained on oxidation of sodium borohydride by iodine is:

1.074 {g/ cm}^{3} . 3. 91 gm

2.50 \times 10^{23}

H .

H

28.0 {cm}^{3}

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