Question

Iodine reacts with concentrated $HN{O}_3$ to yield Y along with other products. The oxidation state of iodine in Y, is

• A. 5
• B. 3
• C. 1
• D. 7

Answer 1

The correct option is A 5

The reaction of Iodine with concentrated nitric acid is given by -
$I_2+10HN{O}_3\to 2HI{O}_3+10N{O}_2+4H_{2}O$
The product Y is $HI{O}_3$
The oxidation state of Y from $HI{O}_3$ can be found as -
As the hydrogen = +1
And one Oxygen atom = -2
Thus, three oxygen atoms = -6
And for I be it's ‘x’.
So, the oxidation state can be found as
$1+x+(-6)=01+x-6=0x=6-1x=5$