Iodine reacts with hypo to give:

$N a I$

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$N a_{2} S O_{3}$

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$N a_{2} S_{4} O_{6}$

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$N a_{2} S O_{4}$

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Solution

The correct option is C
$N a_{2} S_{4} O_{6}$

Hypo is sodium thiosulphate - $2 N a_{2} S_{2} O_{3}$ :

$2 N a_{2} S_{2} O_{3} + I_{2} ⟶ 2 N a I + N a_{2} S_{4} O_{6}$

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