Question

Iodoform can be obtained on warming $NaOH$ and iodine with:

• A. $C{H}_3-C{H}_2-CH\left(OH\right)-C{H}_3$
• B. $(C{H}_3{)}_2-C{H}_2-\stackrel{O}{\stackrel{||}{C}}-C_2{H}_5$
• C. $C{H}_3-\stackrel{O}{\stackrel{||}{C}}-O-C{H}_3$
• D. $(C{H}_3{)}_2-C{H}_2-C{H}_{2}OH$

Answer 1

The correct option is A $C{H}_3-C{H}_2-CH\left(OH\right)-C{H}_3$

Methyl ketones and $-\stackrel{OH}{\stackrel{|}{C}}H-C{H}_3$ gives the iodoform test.

Carboxylic acid and its derivatives do not give the test as there is no free existence of the $C=O$ group (due to resonance) which is required for the reaction.