Ion with highest polarizing power is ______.

${M g}^{2 +}$

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${C a}^{2 +}$

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${A l}^{3 +}$

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${N a}^{+}$

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Solution

The correct option is C
${A l}^{3 +}$

Some facts before answering the question:-

(a) Cations are smaller than their parent atoms.

(b) Across the period from left, size of atom decreases

(c) Down the group, atomic size increases

On comparing the ratios, $ϕ_{A l}$ is the maximum among the given cations. Thus, it has the highest polarizing power.

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Similar questions

Q. Arrange the following in the order given below:

Increasing polarising power of

{N a}^{+}, {C a}^{2 +}, {M g}^{2 +}, {A l}^{3 +}

is :

{C a}^{2 +} < {N a}^{+} < {M g}^{2 +} < {A l}^{3 +}

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Q. Arrange the following in the decreasing order of their coagulation power:

A l^{3 +}, N a^{+}, C a^{2 +}

The charge/ size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, $K^{+}, C a^{2 +}, M g^{2 +}, B e^{2 +}$

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

N a^{+}

M g^{2 +}

A l^{3 +}

and

S i^{4 +}

are isoelectronic, their ionic size will follow the order:

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