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Solubility Product

Ionic conduct...

Question

Ionic conductance of H+ and So4_ are x and y cms^- . Find the equivalent conductance of HSO4 1] 2x+ y/2 2] x+y/2 3] x/2+y 3]x/2 +y/2

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H^{+}

{S O}_{4}^{2 -}

x

y S {c m}^{2} {m o l}^{- 1}

H_{2} {S O}_{4}

C_{2} O_{4}^{2 -}, K^{+},

N a^{+}

c m^{2} E q^{- 1}

A_{e q}^{0}

(N a O O C - C O O K)

\frac{x + 4}{3} = \frac{y - 1}{5} = \frac{z + 3}{4} and \frac{x + 1}{1} = \frac{y - 4}{1} = \frac{z - 5}{2}

\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{- 3} and \frac{x + 3}{- 1} = \frac{y - 5}{8} = \frac{z - 1}{4}

\frac{5 - x}{- 2} = \frac{y + 3}{1} = \frac{1 - z}{3} and \frac{x}{3} = \frac{1 - y}{- 2} = \frac{z + 5}{- 1}

\frac{x - 2}{3} = \frac{y + 3}{- 2}, z = 5 and \frac{x + 1}{1} = \frac{2 y - 3}{3} = \frac{z - 5}{2}

\frac{x - 5}{1} = \frac{2 y + 6}{- 2} = \frac{z - 3}{1} and \frac{x - 2}{3} = \frac{y + 1}{4} = \frac{z - 6}{5}

\frac{- x + 2}{- 2} = \frac{y - 1}{7} = \frac{z + 3}{- 3} and \frac{x + 2}{- 1} = \frac{2 y - 8}{4} = \frac{z - 5}{4}

B a S O_{4}

o h m^{- 1} c m^{2} e q v^{- 1}

4 \times 10^{- 5} o h m^{- 1} c m^{- 1} . K_{s p}

B a S O_{4} x \times 10^{- y} M^{2}

If $2 x + y = 23$ and $4 x - y = 19$ ; find the values of $x - 3 y$ and $5 y - 2 x .$

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