Question

Ionization potential $\alpha$ $\frac{1}{AtomicRadius}$ (True/False)

• A. True
• B. False

Answer 1

The correct option is A

True

Atomic radius: The values of ionization potential of an element decreases as its atomic radius increases. This is because the electrostatic force of attraction between the nucleus and the outermost electron decreases as the distance between them increases. So the energy required for the removal of the electron will comparatively be less

Ionization potential $\alpha$ $\frac{1}{AtomicRadius}$