Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atom in ground state is excited by monochromatic light of energy 12.1 eV. The spectral lines emitted by hydrogen according to Bohr's theory will be:
A
One
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B
Two
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C
Three
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D
Four
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Solution
The correct option is C Three
ΔE=−13.6−E2=12.1eV E2=1.5eV
The final state corresponds to n = 3. Total number of lines observed =n2×(n2−1)2=3