Ionization potential of hydrogen atom is 13.6 V Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be
A
One
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B
Two
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C
Three
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D
Four
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Solution
The correct option is CThree Final energy of electron = -13.6 + 12.1 = -1.51 eV which is corresonds to third level i.e. n = 3. Hence number of spectral lines emitted =n(n−1)2=3(3−1)2=3