Question

Ionization potential of $Na$ would be numerically the same as :

• A. electron affinity of $N{a}^{+}$
• B. electronegativity of $N{a}^{+}$
• C. electron affinity of $Na$
• D. ionization potential of $Mg$

Answer 1

The correct option is A electron affinity of $N{a}^{+}$

Ionization energy: the energy required to remove an electron from a neutral atom.
Electron affinity: the energy change when a neutral atom attracts an electron to become a negative ion.
So, ionization potential of Na would be numerically the same as electron affinity of $N{a}^{+}$.