You visited us 15 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Circular Kinematics

Ionized hydro...

Question

Ionized hydrogen atoms and $α$ -particles with same momenta enters perpendicular to a constant magnetic field $B$ . The ratio of radii of their paths i.e. $r_{H} : r_{α}$ will be

2 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 2 : 1
$\frac{q_{H}}{q_{α}} = \frac{1}{2} r = \frac{m v}{q B}$
For same momenta, $r \propto \frac{1}{q}$
$\frac{r_{H}}{r_{α}} = \frac{q_{α}}{q_{H}} = \frac{2}{1}$

Suggest Corrections

Similar questions

Q. Ionized hydrogen atoms and

α

-particles with same momenta enters perpendicular to a constant magnetic field

B

. The ratio of radii of their paths i.e.

r_{H} : r_{α}

will be

Q. A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

(i i i)

If proton and

α

- particle enter the magnetic field, perpendicular to it with same momentum, then the ratio of the radii of curvature of proton and

α

- particle will be

[

1 Mark

]

Q. A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

(i v)

If proton and

α

- particle enter the magnetic field, perpendicular to it with same kinetic energy, then the ratio of the radii of curvature of proton and

α

- particle will be

[

1 Mark

]

Q. A proton and an

α

- particle (Helium nucleus) enters a uniform magnetic field with their direction of velocity perpendicular to the direction of magnetic field.

(i i)

If proton and

α

- particle enter the magnetic field, perpendicular to it with same velocity, then the ratio of the radii of curvature of proton and

α

- particle will be

[

1 Mark

]

Q. A proton, deutron and an

α

-particle enter a magnetic field perpendicular to field with same velocity. What is the ratio of the radii of circular paths?

Join BYJU'S Learning Program

Ionized hydrogen atoms and α-particles with same momenta enters perpendicular to a constant magnetic field B. The ratio of radii of their paths i.e. rH:rα will be

The correct option is A 2 : 1 qHqα=12 r = mvqB For same momenta, r∝1q rHrα=qαqH=21

Ionized hydrogen atoms and $α$ -particles with same momenta enters perpendicular to a constant magnetic field $B$ . The ratio of radii of their paths i.e. $r_{H} : r_{α}$ will be

The correct option is A 2 : 1
$\frac{q_{H}}{q_{α}} = \frac{1}{2} r = \frac{m v}{q B}$
For same momenta, $r \propto \frac{1}{q}$
$\frac{r_{H}}{r_{α}} = \frac{q_{α}}{q_{H}} = \frac{2}{1}$