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Standard XII

Chemistry

Introduction to Imperfections in Solids

Ions replace ...

Question

Ions replace Na+ ions at the edge centers of NaCI lattice then the number of vacancies in $1$ mole of NaCl be:

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Solution

$N a^{+}$ the number of atoms $= 12 \times \frac{1}{4} = 3$
And
$3 N a^{+} = A l^{3 +}$
Then for 1 mole that is $1 \times 6 \times 10^{23}$ atoms of $N a^{+}$ would have $= \frac{6 \times 10^{23}}{3 A l^{3 +}}$ atoms = $2 \times 10^{23} a t o m s$ .

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Ions replace Na+ ions at the edge centers of NaCI lattice then the number of vacancies in 1 mole of NaCl be:

Na+ the number of atoms =12×14=3And 3Na+=Al3+Then for 1 mole that is 1×6×1023 atoms of Na+ would have =6×10233Al3+ atoms =2×1023atoms.

Ions replace Na+ ions at the edge centers of NaCI lattice then the number of vacancies in $1$ mole of NaCl be:

$N a^{+}$ the number of atoms $= 12 \times \frac{1}{4} = 3$
And
$3 N a^{+} = A l^{3 +}$
Then for 1 mole that is $1 \times 6 \times 10^{23}$ atoms of $N a^{+}$ would have $= \frac{6 \times 10^{23}}{3 A l^{3 +}}$ atoms = $2 \times 10^{23} a t o m s$ .