IP 1 and IP 2 of Mg are 178 and 348 K cal mol -1 respectively- The energy required for the reaction Mg - Mg 2-2 e -is-A- -170 K cal mol -1B- -526 K cal mol -1C- -170 K cal mol -1D- -526 K cal mol -1

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Ionization Enthalpy

IP 1 and IP 2...

Question

$I P_{1}$ and $I P_{2}$ of $M g$ are 178 and $348 {K cal mol}^{- 1}$ respectively. The energy required for the reaction
$M g \to M g^{2 +} + 2 e^{-}$ is:

+ 170 {K cal mol}^{- 1}

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+ 526 {K cal mol}^{- 1}

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- 170 {K cal mol}^{- 1}

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- 526 {K cal mol}^{- 1}

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I P_{1}

I P_{2}

M g

^{- 1}

M g \to M g^{2 +} + 2 e^{-}

$I P_{1}$ and $I P_{2}$ of Mg are 178 and 348 k cal ${m o l}^{- 1}$ . The energy required for the reaction Mg $\to$ ${M g}^{2 +}$ + 2 $e^{-}$ is

$I P_{1}$ and $I P_{2}$ of Mg are 178 and 348 K cal ${m o l}^{- 1}$ . The energy required for the reaction Mg $\to$ ${M g}^{2 +}$ + 2 $e^{-}$ is

I P_{1}

I P_{2}

M g

^{- 1}

M g \to M g^{2 +} + 2 e^{-}

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