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Question

Iron oxide has formula Fe0.94O. The fraction of Fe exists as Fe+3 is

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Solution

Iron oxide has formula Fe0.94O.
Let there be 100 oxide ions and 94 iron ions.
Fe+x:O2=94:100
Total negative charge on 100 oxide ions =200
It means as per the concept of charge neutrality, 94 iron ions should have total charge of +200.
Let number of Fe+3=X
Number of Fe+2=(94X)
Total positive charge =3X+2(94X)=200X=12
Percentage of Fe+3=1294×100=12.8%

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