Question

Is 0 a term of the AP: 31, 28, 25, ...?
If true then enter $1$ and if false then enter $0$

Answer 1

The given sequence is an AP with first term $a=31$ and common difference $d=-3$
Let us consider that $0$ is a term of the AP

Let $a_n=0$

$\Rightarrow a+(n-1)d=0$

$\Rightarrow 31+(n-1)\times -3=0$

$\Rightarrow n=\frac{31}{3}+1$

$=\frac{34}{3}$

$=11\frac{1}{3}$

Since $n$ is a fraction which is not possible.

Hence $0$ is not a term of an AP.