Is $219$ divisible by $3$ ?

Open in App

Solution

A number is divisible by $3$ if the sum of its digits is divisible by $3$ .
The given number is $219$ . The sum of its digits is $2 + 1 + 9 = 12$ .
The sum of its digits is divisible by $3$ .
Therefore, $219$ is divisible by $3$ .

Suggest Corrections

Similar questions

Show that:

$(i) 13^{3} - 5^{3}$ is divisible by 8.

$(i i) 35^{3} + 27^{3}$ is divisible by 62.

Suppose a 3-digit number is divisible by 3. Prove that is divisible by 9.

$\frac{219}{__} = 2 \frac{3}{35}$

If P(k) is the statement 2^3k - 1 is divisible by 7, then P(k + 1) is

Join BYJU'S Learning Program