is a factor of $4 x y + 2 y + 6 x + 3$ .

(2 x + 3) (2 y + 3)

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(2 x + 1) (y + 3)

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(2 x + 1) (2 y + 6)

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(2 x + 1) (2 y + 3)

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Solution

The correct option is D $(2 x + 1) (2 y + 3)$
Given, the expression is $4 x y + 2 y + 6 x + 3$ .
Clubbing the first two and last two terms, we get,
$(4 x y + 2 y) + (6 x + 3)$
= $2 y (2 x + 1) + 3 (2 x + 1)$
= $(2 x + 1) (2 y + 3)$

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