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Question

is a factor of 4xy+2y+6x+3.

A
(2x+3)(2y+3)
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B
(2x+1)(y+3)
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C
(2x+1)(2y+6)
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D
(2x+1)(2y+3)
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Solution

The correct option is D (2x+1)(2y+3)
Given, the expression is 4xy+2y+6x+3.
Clubbing the first two and last two terms, we get,
(4xy+2y)+(6x+3)
= 2y(2x+1)+3(2x+1)
= (2x+1)(2y+3)

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