The correct option is C x+2y=3
The point on a line satisfies the equation of that line.
Substitue the value of coordinates (x = 3, y = 0) in
1.x+2y=5
3 + 2(0) = 3 ≠ 5 → (x+2y=5 does not passes through (3, 0)
2.x−2y=−3
3 - 2(0) = 3 ≠ -3 → x−2y=−3 does not passes through (3, 0)
3.x+2y=3
3 + 2(0) = 3 → x+2y=3 passes through (3, 0)
4. 2x+y=4
2(3) + ) = 6 ≠ 4 → 2x+y=4 does not passes through (3, 0)