.................. is a solution of quadratic equation $2 x^{2} - x - 3 = 0$ .

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $- 1$
$2 x^{2} - x - 3 = 0$

$∴ 2 x^{2} - 3 x + 2 x - 3 = 0$

$∴ x (2 x - 3) + 1 (2 x - 3) = 0$

$∴ (2 x - 3) (x + 1) = 0$

$∴ 2 x - 3 = 0$ and $x + 1 = 0$

$∴ x = \frac{3}{2}$ or $x = - 1$

Hence, option B is correct.

Suggest Corrections

Similar questions

Using quadratic formula find the roots of the quadratic equation $2 x^{2} - 7 x + 3 = 0$ .

2 (x^{2} + \frac{1}{x^{2}}) - 9 (x - \frac{1}{x}) + 14 = 0

2 x^{2} - x + \frac{1}{8} = 0

2 x^{2} + x + 1 = 0

x^{2} - 3 x - 10 = 0

2 x^{2} + x - 6 = 0

\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0

2 x^{2} - x + \frac{1}{8} = 0

100 x^{2} - 20 x + 1 = 0

Join BYJU'S Learning Program