Question

is an arithmetic sequence.

• A. $0,1,4,13,...$
• B. $5,12,19,26,..$
• C. $4,9,12,19,...$

Answer 1

The correct option is B $5,12,19,26,..$

Consider $0,1,4,13,...$

$1–0=1$
$4–1=3$

Since the difference between consecutive terms is not a constant, this arrangement is not an arithmetic sequence.

Consider $4,9,12,19,...$

$9–4=5$
$12–9=3$

Since $5\ne 3,$ this arrangement is not an arithmetic sequence.

Consider $5,12,19,26,...$

$12–5=19–12=26–19=7$

The difference between consecutive terms is a constant. Thus, the arrangement is an arithmetic sequence.