Question

Is $\cos {36}^o=\frac{1}{4}(\sqrt{5}+6)$.

State True or False

• A. True
• B. False

Answer 1

The correct option is B False

As we know that

$\cos {36}^{\circ }=\frac{\sqrt{5}+1}{4}$

So the given relation is $\text{False}$