-sin 2 x-cos 2 x-sin 2 x cos 2 x d x is equal toA- tan x- x-CB- tan x-cosec x-CC- -tan x- x-CD- tan x- x-C

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Evaluation of a Determinant

∫sin 2 x-cos ...

Question

is equal to

A. tan x + cot x + C

B. tan x + cosec x + C

C. − tan x + cot x + C

D. tan x + sec x + C

Open in App

Solution

Hence, the correct answer is A.

Suggest Corrections

Similar questions

\int \frac{\cos 2 x - 1}{\cos 2 x + 1} d x =

(a) tan x − x + C
(b) x + tan x + C
(c) x − tan x + C
(d) − x − cot x + C

Choose the correct answer. $\int \frac{s i n^{2} x - c o s^{2} x}{s i n^{2} x c o s^{2} x} d x$ is equal to
$(a)tan x+cot x+C (b)tan x+cosec x+C (c)-tan x+cot x+C (d)tan x+sec x+C$

\int {1 + 2 tan x (tan x + sec x)}^{\frac{1}{2}} d x

is equal to

\int \frac{(1 + \sqrt{t a n x}) (1 + t a n^{2} x)}{2 t a n x} d x

equal to

\int {1 + 2 t a n x (t a n x + s e c x)}^{1 / 2} d x =

Join BYJU'S Learning Program

is equal to A. tan x + cot x + C B. tan x + cosec x + C C. − tan x + cot x + C D. tan x + sec x + C

Hence, the correct answer is A.

is equal to

A. tan x + cot x + C

B. tan x + cosec x + C

C. − tan x + cot x + C

D. tan x + sec x + C