Question

Is it possible to construct $△\mathrm{ABC}$ in which $\mathrm{AB}=6\mathrm{cm}$, $\angle \mathrm{A}=105°$ and $\angle \mathrm{B}=80°$? If not, why?

Answer 1

Step 1: Draw a line $\mathrm{AB}=6\mathrm{cm}$

Step 2: From point A draw $\angle \mathrm{A}=105°$

Step 3: From point B draw $\angle \mathrm{B}=80°$

Sum of $\angle \mathrm{A}$and $\angle \mathrm{B}$ is equal to $105°+80°=185°$ which is contradicting the angle sum property of a triangle.

Hence, the formation of triangle ABC is not possible.