Is it possible to have a polygon whose sum of interior angles is 56 right angles?
Yes
Let the number of sides =n
Sum of interior angles of a polygon =(2n−4)×90∘
Therefore, sum of interior angles of a polygon =(n−2)×180∘
/5628(/901)=(n−2)×/1802
28=n-2
n=30 (a whole numbers)
Hence it is possible to have a polygon whose sum of interior angles is 56 right angles as the number of sides (n)is a whole number.