Is it possible TO have a regular polygon of whose interior angles measures 1*3/4 right angles?

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Solution

Dear student
$G i v e n : M e a s u r e o f i n t e r i o r a n g l e = 1 \frac{3}{4} r i g h t a n g l e = \frac{7}{4} r i g h t a n g l e . N o w, E a c h i n t e r i o r a n g l e o f t h e p o l y g o n = \frac{2 n - 4}{n} r i g h t a n g l e s \Rightarrow \frac{7}{4} = \frac{2 n - 4}{n} 7 n = 8 n - 16 n = 16 S o, i t i s p o s s i b l e t o h a v e a r e g u l a r p o l y g o n .$
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