Question

IS LHS=RHS?

$\sqrt{\frac{\sec \theta -1}{\sec \theta +1}}+\sqrt{\frac{\sec \theta +1}{\sec \theta -1}}=cosec\theta$

Say true or false.

• A. True
• B. False
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is B False

Simplifying, we get
$\frac{sec\theta -1+sec\theta +1}{\sqrt{se{c}^2\theta -1}}$
$=\frac{2sec\theta }{tan\theta }$
$=\frac{2sec\theta }{sin\theta .sec\theta }$
$=2cosec\theta$