$. . . . . . .$ is the $7 t h$ term from last in the A.P. $11, 17, 23, . . . . ., 605$ .

47

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569

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579

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57

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Solution

The correct option is B $569$
The common difference of the given A.P. is $17 - 23 = - 6$ if we take $605$ to be the first term of the A.P.
Then the $7$ th term from the last in the A.P. will be
$605 + (7 - 1) . (- 6)$
$= 605 - 36$
$= 569$ .

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